Hello,

I'm analyzing a Bulk Acoustic Wave with three layers in 2D, two electrodes (5 mm length and 0.1 mm height) each sandwiched with a piezoelectric (5mm length and 0.1mm height). The purpose of the simulation is to actuate a lateral wavelength and achieve resonant frequency and output voltage.

I'm using Designer Module and defined my frequency of interest/damping and Ricker wave with a driving frequency. Also, I defined two geometric interfaces for electrodes, one is a time function and the other is ground. I have achieved the expected resonant frequency from the impedance plot and the voltage response was within expectation too.

My questions are:

1. Is this the correct way to actuate an ultrasonic wave to achieve electrical energy (output voltage)?

2. If yes, this is a transducer that uses ultrasonic wave to convert to electrical energy, is there a way to actuate a magnetic field instead of ultrasonic wave to achieve electrical energy? I want to compare both scenarios to see what magnetic field and what ultrasonic wave will achieve the desired output voltage?

3. In my package, I can also see mechanical dynamic/static modules, where and how can I setup EM module?

4. Also, is there a way to find the output power of both scenarios?

Thanks,

Abdul

### 1 comment

• Hi Abdul,

thanks for your interest in using OnScale.

1. If you want to investigate the effect of an incoming pressure wave, you want to define the pressure excitation as the time signal (so you need to add some propagation medium around the transducer and set up a pressure boundary at the edge of the medium). Next, one electrode should be grounded and the other electrode should be left as 'Open' through a parallel resistor. To have this, you need to create a receiver circuit for this.

2. For the magnetic excitation could you please elaborate a bit more on the mechanism you would like to exploit? Is this an EMAT?

3. The EM module is not yet set up for the Designer module only for Analyst. There are some examples on how to use these at https://support.onscale.com/hc/en-us/sections/360001138477-Optical-Waveguides

4. For the electric output case, from the v(t) and i(t) voltage and current time signals, the instantaneous electric power is p(t)=v(t)*i(t), while in the frequency domain, p(f) = FFT(v(t))*conjugate(FFT(i(t))

Let us know any further questions,

Thanks,

Gergely

Application Engineer, OnScale